(1/x+2)+(1/x^2-2x)-(8/x3-4x)=0

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Solution for (1/x+2)+(1/x^2-2x)-(8/x3-4x)=0 equation: 



(1/x+2)+(1/x^2-2x)-(8/x3-4x)=0



Domain of the equation: x+2)!=0

x∈R





Domain of the equation: x^2-2x)!=0

x∈R





Domain of the equation: x3-4x)!=0

x∈R



We add all the numbers together, and all the variables

(1/x+2)+(1/x^2-2x)-(-4x+8/x3)=0

We get rid of parentheses

1/x+1/x^2-2x+4x-8/x3+2=0

We calculate fractions

We do not support expression: x^6

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